Determine if Continuous h(x)=(4x-3)/(x+2)

h(x)=4x-3x+2
Set the denominator in 4x-3x+2 equal to 0 to find where the expression is undefined.
x+2=0
Subtract 2 from both sides of the equation.
x=-2
The domain is all values of x that make the expression defined.
Interval Notation:
(-∞,-2)∪(-2,∞)
Set-Builder Notation:
{x|x≠-2}
Since the domain is not all real numbers, h(x)=4x-3x+2 is not continuous over all real numbers.
Not continuous
Determine if Continuous h(x)=(4x-3)/(x+2)