h(x)=4x-3x+2

Set the denominator in 4x-3x+2 equal to 0 to find where the expression is undefined.

x+2=0

Subtract 2 from both sides of the equation.

x=-2

The domain is all values of x that make the expression defined.

Interval Notation:

(-∞,-2)∪(-2,∞)

Set-Builder Notation:

{x|x≠-2}

Since the domain is not all real numbers, h(x)=4x-3x+2 is not continuous over all real numbers.

Not continuous

Determine if Continuous h(x)=(4x-3)/(x+2)