Divide (10x^2-13x+12)÷(5x-1)

Math
(10×2-13x+12)÷(5x-1)
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
5x110×213x+12
Divide the highest order term in the dividend 10×2 by the highest order term in divisor 5x.
2x
5x110×213x+12
Multiply the new quotient term by the divisor.
2x
5x110×213x+12
+10×22x
The expression needs to be subtracted from the dividend, so change all the signs in 10×2-2x
2x
5x110×213x+12
10×2+2x
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
2x
5x110×213x+12
10×2+2x
11x
Pull the next terms from the original dividend down into the current dividend.
2x
5x110×213x+12
10×2+2x
11x+12
Divide the highest order term in the dividend -11x by the highest order term in divisor 5x.
2x115
5x110×213x+12
10×2+2x
11x+12
Multiply the new quotient term by the divisor.
2x115
5x110×213x+12
10×2+2x
11x+12
11x+115
The expression needs to be subtracted from the dividend, so change all the signs in -11x+115
2x115
5x110×213x+12
10×2+2x
11x+12
+11x115
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
2x115
5x110×213x+12
10×2+2x
11x+12
+11x115
+495
The final answer is the quotient plus the remainder over the divisor.
2x-115+495(5x-1)
Divide (10x^2-13x+12)÷(5x-1)

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