Divide 39/(2 cube root of 5-1)

Math
39253-1
Multiply 39253-1 by (253)2-(253)⋅-1+(-1)2(253)2-(253)⋅-1+(-1)2.
39253-1⋅(253)2-(253)⋅-1+(-1)2(253)2-(253)⋅-1+(-1)2
Multiply 39253-1 and (253)2-(253)⋅-1+(-1)2(253)2-(253)⋅-1+(-1)2.
39((253)2-(253)⋅-1+(-1)2)(253-1)((253)2-(253)⋅-1+(-1)2)
Expand the denominator using the FOIL method.
39((253)2-(253)⋅-1+(-1)2)253(253)2+4532+253(-1)2-(253)2-253+(-1)3
Simplify.
39((253)2-(253)⋅-1+(-1)2)39
Cancel the common factor of 39.
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Cancel the common factor.
39((253)2-(253)⋅-1+(-1)2)39
Divide (253)2-(253)⋅-1+(-1)2 by 1.
(253)2-(253)⋅-1+(-1)2
(253)2-(253)⋅-1+(-1)2
Simplify each term.
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Apply the product rule to 253.
22532-(253)⋅-1+(-1)2
Raise 2 to the power of 2.
4532-(253)⋅-1+(-1)2
Rewrite 532 as (52)13.
4523-(253)⋅-1+(-1)2
Raise 5 to the power of 2.
4253-(253)⋅-1+(-1)2
Multiply 2 by -1.
4253-253⋅-1+(-1)2
Multiply -1 by -2.
4253+253+(-1)2
Raise -1 to the power of 2.
4253+253+1
4253+253+1
The result can be shown in multiple forms.
Exact Form:
4253+253+1
Decimal Form:
16.11602284…
Divide 39/(2 cube root of 5-1)

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