Divide ((3x^3)/(4y))÷(x/(9y))

$\frac{3 x^{3}}{4 y} \div \frac{x}{9 y}$

To divide by a fraction, multiply by its reciprocal.

$\frac{3 x^{3}}{4 y} \cdot \frac{9 y}{x}$

Cancel the common factor of $x$ .

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Factor $x$ out of $3 x^{3}$ .

$\frac{x (3 x^{2})}{4 y} \cdot \frac{9 y}{x}$

Cancel the common factor.

$\frac{x (3 x^{2})}{4 y} \cdot \frac{9 y}{x}$

Rewrite the expression.

$\frac{3 x^{2}}{4 y} (9 y)$

Cancel the common factor of $y$ .

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Factor $y$ out of $4 y$ .

$\frac{3 x^{2}}{y \cdot 4} (9 y)$

Factor $y$ out of $9 y$ .

$\frac{3 x^{2}}{y \cdot 4} (y \cdot 9)$

Cancel the common factor.

$\frac{3 x^{2}}{y \cdot 4} (y \cdot 9)$

Rewrite the expression.

$\frac{3 x^{2}}{4} \cdot 9$

Combine $\frac{3 x^{2}}{4}$ and $9$ .

$\frac{3 x^{2} \cdot 9}{4}$

Multiply $9$ by $3$ .

$\frac{27 x^{2}}{4}$

Divide ((3x^3)/(4y))÷(x/(9y))

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