Divide (4x^2+7x-3)/(x+1)

Math
4×2+7x-3x+1
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
x+14×2+7x3
Divide the highest order term in the dividend 4×2 by the highest order term in divisor x.
4x
x+14×2+7x3
Multiply the new quotient term by the divisor.
4x
x+14×2+7x3
+4×2+4x
The expression needs to be subtracted from the dividend, so change all the signs in 4×2+4x
4x
x+14×2+7x3
4×24x
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
4x
x+14×2+7x3
4×24x
+3x
Pull the next terms from the original dividend down into the current dividend.
4x
x+14×2+7x3
4×24x
+3x3
Divide the highest order term in the dividend 3x by the highest order term in divisor x.
4x+3
x+14×2+7x3
4×24x
+3x3
Multiply the new quotient term by the divisor.
4x+3
x+14×2+7x3
4×24x
+3x3
+3x+3
The expression needs to be subtracted from the dividend, so change all the signs in 3x+3
4x+3
x+14×2+7x3
4×24x
+3x3
3x3
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
4x+3
x+14×2+7x3
4×24x
+3x3
3x3
6
The final answer is the quotient plus the remainder over the divisor.
4x+3-6x+1
Divide (4x^2+7x-3)/(x+1)

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