Divide (5x^2+14x+3)÷(x+2)

Math
(5×2+14x+3)÷(x+2)
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
x+25×2+14x+3
Divide the highest order term in the dividend 5×2 by the highest order term in divisor x.
5x
x+25×2+14x+3
Multiply the new quotient term by the divisor.
5x
x+25×2+14x+3
+5×2+10x
The expression needs to be subtracted from the dividend, so change all the signs in 5×2+10x
5x
x+25×2+14x+3
5×210x
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
5x
x+25×2+14x+3
5×210x
+4x
Pull the next terms from the original dividend down into the current dividend.
5x
x+25×2+14x+3
5×210x
+4x+3
Divide the highest order term in the dividend 4x by the highest order term in divisor x.
5x+4
x+25×2+14x+3
5×210x
+4x+3
Multiply the new quotient term by the divisor.
5x+4
x+25×2+14x+3
5×210x
+4x+3
+4x+8
The expression needs to be subtracted from the dividend, so change all the signs in 4x+8
5x+4
x+25×2+14x+3
5×210x
+4x+3
4x8
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
5x+4
x+25×2+14x+3
5×210x
+4x+3
4x8
5
The final answer is the quotient plus the remainder over the divisor.
5x+4-5x+2
Divide (5x^2+14x+3)÷(x+2)

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