Divide (5x^2+18x+6)÷(x+3)

Math
(5×2+18x+6)÷(x+3)
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
x+35×2+18x+6
Divide the highest order term in the dividend 5×2 by the highest order term in divisor x.
5x
x+35×2+18x+6
Multiply the new quotient term by the divisor.
5x
x+35×2+18x+6
+5×2+15x
The expression needs to be subtracted from the dividend, so change all the signs in 5×2+15x
5x
x+35×2+18x+6
5×215x
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
5x
x+35×2+18x+6
5×215x
+3x
Pull the next terms from the original dividend down into the current dividend.
5x
x+35×2+18x+6
5×215x
+3x+6
Divide the highest order term in the dividend 3x by the highest order term in divisor x.
5x+3
x+35×2+18x+6
5×215x
+3x+6
Multiply the new quotient term by the divisor.
5x+3
x+35×2+18x+6
5×215x
+3x+6
+3x+9
The expression needs to be subtracted from the dividend, so change all the signs in 3x+9
5x+3
x+35×2+18x+6
5×215x
+3x+6
3x9
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
5x+3
x+35×2+18x+6
5×215x
+3x+6
3x9
3
The final answer is the quotient plus the remainder over the divisor.
5x+3-3x+3
Divide (5x^2+18x+6)÷(x+3)

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