Divide (6x^2+21x+6)/(2x+5)

Math
6×2+21x+62x+5
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
2x+56×2+21x+6
Divide the highest order term in the dividend 6×2 by the highest order term in divisor 2x.
3x
2x+56×2+21x+6
Multiply the new quotient term by the divisor.
3x
2x+56×2+21x+6
+6×2+15x
The expression needs to be subtracted from the dividend, so change all the signs in 6×2+15x
3x
2x+56×2+21x+6
6×215x
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
3x
2x+56×2+21x+6
6×215x
+6x
Pull the next terms from the original dividend down into the current dividend.
3x
2x+56×2+21x+6
6×215x
+6x+6
Divide the highest order term in the dividend 6x by the highest order term in divisor 2x.
3x+3
2x+56×2+21x+6
6×215x
+6x+6
Multiply the new quotient term by the divisor.
3x+3
2x+56×2+21x+6
6×215x
+6x+6
+6x+15
The expression needs to be subtracted from the dividend, so change all the signs in 6x+15
3x+3
2x+56×2+21x+6
6×215x
+6x+6
6x15
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
3x+3
2x+56×2+21x+6
6×215x
+6x+6
6x15
9
The final answer is the quotient plus the remainder over the divisor.
3x+3-92x+5
Divide (6x^2+21x+6)/(2x+5)

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