9y6y-5

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.

6y | – | 5 | 9y | + | 0 |

Divide the highest order term in the dividend 9y by the highest order term in divisor 6y.

32 | |||||||

6y | – | 5 | 9y | + | 0 |

Multiply the new quotient term by the divisor.

32 | |||||||

6y | – | 5 | 9y | + | 0 | ||

+ | 9y | – | 152 |

The expression needs to be subtracted from the dividend, so change all the signs in 9y-152

32 | |||||||

6y | – | 5 | 9y | + | 0 | ||

– | 9y | + | 152 |

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

32 | |||||||

6y | – | 5 | 9y | + | 0 | ||

– | 9y | + | 152 | ||||

+ | 152 |

The final answer is the quotient plus the remainder over the divisor.

32+152(6y-5)

Divide (9y)/(6y-5)