9y6y-5
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
| 6y | – | 5 | 9y | + | 0 |
Divide the highest order term in the dividend 9y by the highest order term in divisor 6y.
| 32 | |||||||
| 6y | – | 5 | 9y | + | 0 |
Multiply the new quotient term by the divisor.
| 32 | |||||||
| 6y | – | 5 | 9y | + | 0 | ||
| + | 9y | – | 152 |
The expression needs to be subtracted from the dividend, so change all the signs in 9y-152
| 32 | |||||||
| 6y | – | 5 | 9y | + | 0 | ||
| – | 9y | + | 152 |
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
| 32 | |||||||
| 6y | – | 5 | 9y | + | 0 | ||
| – | 9y | + | 152 | ||||
| + | 152 |
The final answer is the quotient plus the remainder over the divisor.
32+152(6y-5)
Divide (9y)/(6y-5)
