Divide (n^2+6n+8)/(n+3)

Math
n2+6n+8n+3
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
n+3n2+6n+8
Divide the highest order term in the dividend n2 by the highest order term in divisor n.
n
n+3n2+6n+8
Multiply the new quotient term by the divisor.
n
n+3n2+6n+8
+n2+3n
The expression needs to be subtracted from the dividend, so change all the signs in n2+3n
n
n+3n2+6n+8
n23n
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
n
n+3n2+6n+8
n23n
+3n
Pull the next terms from the original dividend down into the current dividend.
n
n+3n2+6n+8
n23n
+3n+8
Divide the highest order term in the dividend 3n by the highest order term in divisor n.
n+3
n+3n2+6n+8
n23n
+3n+8
Multiply the new quotient term by the divisor.
n+3
n+3n2+6n+8
n23n
+3n+8
+3n+9
The expression needs to be subtracted from the dividend, so change all the signs in 3n+9
n+3
n+3n2+6n+8
n23n
+3n+8
3n9
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
n+3
n+3n2+6n+8
n23n
+3n+8
3n9
1
The final answer is the quotient plus the remainder over the divisor.
n+3-1n+3
Divide (n^2+6n+8)/(n+3)

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