Evaluate (10^-6)/(10^-8)

$\frac{10^{- 6}}{10^{- 8}}$

Move $10^{- 8}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$10^{- 6} \cdot 10^{8}$

Multiply $10^{- 6}$ by $10^{8}$ by adding the exponents.

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Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$10^{- 6 + 8}$

Add $- 6$ and $8$ .

$10^{2}$

Raise $10$ to the power of $2$ .

$100$

Evaluate (10^-6)/(10^-8)

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