Evaluate e^(-2 natural log of 10)

$e^{- 2 \ln (10)}$

Simplify $- 2 \ln (10)$ by moving $2$ inside the logarithm.

$e^{- \ln (10^{2})}$

Raise $10$ to the power of $2$ .

$e^{- \ln (100)}$

The result can be shown in multiple forms.

Exact Form:

$e^{- \ln (100)}$

Decimal Form:

$0.01$

Evaluate e^(-2 natural log of 10)

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