Evaluate f(0.99)=(x^3-x)/(x-1)

$f (0.99) = \frac{x^{3} - x}{x - 1}$

Replace the variable $x$ with $0.99$ in the expression.

$f (0.99) = \frac{{(0.99)}^{3} - (0.99)}{(0.99) - 1}$

Simplify the result.

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Simplify the numerator.

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Raise $0.99$ to the power of $3$ .

$f (0.99) = \frac{0.970299 - (0.99)}{(0.99) - 1}$

Multiply $- 1$ by $0.99$ .

$f (0.99) = \frac{0.970299 - 0.99}{(0.99) - 1}$

Subtract $0.99$ from $0.970299$ .

$f (0.99) = \frac{- 0.019701}{(0.99) - 1}$

Subtract $1$ from $0.99$ .

$f (0.99) = \frac{- 0.019701}{- 0.01}$

Divide $- 0.019701$ by $- 0.01$ .

$f (0.99) = 1.9701$

The final answer is $1.9701$ .

$1.9701$

Evaluate f(0.99)=(x^3-x)/(x-1)

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