Evaluate integral of 8x with respect to x

$\int 8 x d x$

Since $8$ is constant with respect to $x$ , move $8$ out of the integral.

$8 \int x d x$

By the Power Rule, the integral of $x$ with respect to $x$ is $\frac{1}{2} x^{2}$ .

$8 (\frac{1}{2} x^{2} + C)$

Simplify the answer.

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Simplify.

$8 (\frac{1}{2} x^{2}) + C$

Simplify.

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Combine $\frac{1}{2}$ and $x^{2}$ .

$8 \frac{x^{2}}{2} + C$

Combine $8$ and $\frac{x^{2}}{2}$ .

$\frac{8 x^{2}}{2} + C$

Cancel the common factor of $8$ and $2$ .

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Factor $2$ out of $8 x^{2}$ .

$\frac{2 (4 x^{2})}{2} + C$

Cancel the common factors.

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Factor $2$ out of $2$ .

$\frac{2 (4 x^{2})}{2 (1)} + C$

Cancel the common factor.

$\frac{2 (4 x^{2})}{2 \cdot 1} + C$

Rewrite the expression.

$\frac{4 x^{2}}{1} + C$

Divide $4 x^{2}$ by $1$ .

$4 x^{2} + C$

Evaluate integral of 8x with respect to x

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