Evaluate limit as x approaches 0 of x/(sin(x))

$lim_{x \to 0} \frac{x}{\sin (x)}$

Evaluate the limit of the numerator and the limit of the denominator.

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Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to 0} x}{lim_{x \to 0} \sin (x)}$

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{lim_{x \to 0} \sin (x)}$

Evaluate the limit of the denominator.

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Move the limit inside the trig function because sine is continuous.

$\frac{0}{\sin (lim_{x \to 0} x)}$

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{\sin (0)}$

The exact value of $\sin (0)$ is $0$ .

$\frac{0}{0}$

The expression contains a division by $0$ The expression is undefined.

Undefined

$\frac{0}{0}$

The expression contains a division by $0$ The expression is undefined.

Undefined

$\frac{0}{0}$

Since $\frac{0}{0}$ is of indeterminate form, apply L’Hospital’s Rule. L’Hospital’s Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 0} \frac{x}{\sin (x)} = lim_{x \to 0} \frac{\frac{d}{d x} [x]}{\frac{d}{d x} [\sin (x)]}$

Find the derivative of the numerator and denominator.

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Differentiate the numerator and denominator.

$lim_{x \to 0} \frac{\frac{d}{d x} [x]}{\frac{d}{d x} [\sin (x)]}$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to 0} \frac{1}{\frac{d}{d x} [\sin (x)]}$

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$lim_{x \to 0} \frac{1}{\cos (x)}$

Convert from $\frac{1}{\cos (x)}$ to $\sec (x)$ .

$lim_{x \to 0} \sec (x)$

Move the limit inside the trig function because secant is continuous.

$\sec (lim_{x \to 0} x)$

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\sec (0)$

The exact value of $\sec (0)$ is $1$ .

$1$

Evaluate limit as x approaches 0 of x/(sin(x))

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