Evaluate limit as x approaches 0 of xsin(1/x) - MathMaster

Math

$lim_{x \to 0} x \sin (\frac{1}{x})$

Since $x \cdot - 1 \leq x \sin (\frac{1}{x}) \leq x \cdot 1$ and $lim_{x \to 0} x \cdot - 1 = lim_{x \to 0} x \cdot 1 = 0$ , apply the squeeze theorem.

$0$

Evaluate limit as x approaches 0 of xsin(1/x)

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