Evaluate square root of 25/pi

$\sqrt{\frac{25}{π}}$

Rewrite $\sqrt{\frac{25}{π}}$ as $\frac{\sqrt{25}}{\sqrt{π}}$ .

$\frac{\sqrt{25}}{\sqrt{π}}$

Simplify the numerator.

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Rewrite $25$ as $5^{2}$ .

$\frac{\sqrt{5^{2}}}{\sqrt{π}}$

Pull terms out from under the radical, assuming positive real numbers.

$\frac{5}{\sqrt{π}}$

Multiply $\frac{5}{\sqrt{π}}$ by $\frac{\sqrt{π}}{\sqrt{π}}$ .

$\frac{5}{\sqrt{π}} \cdot \frac{\sqrt{π}}{\sqrt{π}}$

Combine and simplify the denominator.

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Multiply $\frac{5}{\sqrt{π}}$ and $\frac{\sqrt{π}}{\sqrt{π}}$ .

$\frac{5 \sqrt{π}}{\sqrt{π} \sqrt{π}}$

Raise $\sqrt{π}$ to the power of $1$ .

$\frac{5 \sqrt{π}}{{\sqrt{π}}^{1} \sqrt{π}}$

Raise $\sqrt{π}$ to the power of $1$ .

$\frac{5 \sqrt{π}}{{\sqrt{π}}^{1} {\sqrt{π}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{5 \sqrt{π}}{{\sqrt{π}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{5 \sqrt{π}}{{\sqrt{π}}^{2}}$

Rewrite ${\sqrt{π}}^{2}$ as $π$ .

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Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{π}$ as $π^{\frac{1}{2}}$ .

$\frac{5 \sqrt{π}}{{(π^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{5 \sqrt{π}}{π^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{5 \sqrt{π}}{π^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{5 \sqrt{π}}{π^{\frac{2}{2}}}$

Divide $1$ by $1$ .

$\frac{5 \sqrt{π}}{π^{1}}$

Simplify.

$\frac{5 \sqrt{π}}{π}$

The result can be shown in multiple forms.

Exact Form:

$\frac{5 \sqrt{π}}{π}$

Decimal Form:

$2.82094791 \dots$

Evaluate square root of 25/pi

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