Expand log base 3 of 1/81

$\log_{3} (\frac{1}{81})$

Rewrite $\log_{3} (\frac{1}{81})$ as $\log_{3} (1) - \log_{3} (81)$ .

$\log_{3} (1) - \log_{3} (81)$

Logarithm base $3$ of $1$ is $0$ .

$0 - \log_{3} (81)$

Logarithm base $3$ of $81$ is $4$ .

$0 - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$0 - 4$

Subtract $4$ from $0$ .

$- 4$

Expand log base 3 of 1/81

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