Expand log base 4 of 64x - MathMaster

Math

$\log_{4} (64 x)$

Rewrite $\log_{4} (64 x)$ as $\log_{4} (64) + \log_{4} (x)$ .

$\log_{4} (64) + \log_{4} (x)$

Logarithm base $4$ of $64$ is $3$ .

$3 + \log_{4} (x)$

Expand log base 4 of 64x

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