Factor 25n^2-16 - MathMaster

$25 n^{2} - 16$

Rewrite $25 n^{2}$ as ${(5 n)}^{2}$ .

${(5 n)}^{2} - 16$

Rewrite $16$ as $4^{2}$ .

${(5 n)}^{2} - 4^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 5 n$ and $b = 4$ .

$(5 n + 4) (5 n - 4)$

Factor 25n^2-16

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