Factor 2x^3-2x^2-8x+8

$2 x^{3} - 2 x^{2} - 8 x + 8$

Factor $2$ out of $2 x^{3} - 2 x^{2} - 8 x + 8$ .

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Factor $2$ out of $2 x^{3}$ .

$2 (x^{3}) - 2 x^{2} - 8 x + 8$

Factor $2$ out of $- 2 x^{2}$ .

$2 (x^{3}) + 2 (- x^{2}) - 8 x + 8$

Factor $2$ out of $- 8 x$ .

$2 (x^{3}) + 2 (- x^{2}) + 2 (- 4 x) + 8$

Factor $2$ out of $8$ .

$2 (x^{3}) + 2 (- x^{2}) + 2 (- 4 x) + 2 (4)$

Factor $2$ out of $2 (x^{3}) + 2 (- x^{2})$ .

$2 (x^{3} - x^{2}) + 2 (- 4 x) + 2 (4)$

Factor $2$ out of $2 (x^{3} - x^{2}) + 2 (- 4 x)$ .

$2 (x^{3} - x^{2} - 4 x) + 2 (4)$

Factor $2$ out of $2 (x^{3} - x^{2} - 4 x) + 2 (4)$ .

$2 (x^{3} - x^{2} - 4 x + 4)$

Factor out the greatest common factor from each group.

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Group the first two terms and the last two terms.

$2 ((x^{3} - x^{2}) - 4 x + 4)$

Factor out the greatest common factor (GCF) from each group.

$2 (x^{2} (x - 1) - 4 (x - 1))$

Factor the polynomial by factoring out the greatest common factor, $x - 1$ .

$2 ((x - 1) (x^{2} - 4))$

Rewrite $4$ as $2^{2}$ .

$2 ((x - 1) (x^{2} - 2^{2}))$

Factor.

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Factor.

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Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$2 ((x - 1) ((x + 2) (x - 2)))$

Remove unnecessary parentheses.

$2 ((x - 1) (x + 2) (x - 2))$

Remove unnecessary parentheses.

$2 (x - 1) (x + 2) (x - 2)$

Factor 2x^3-2x^2-8x+8

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