Factor 36n^2-25 - MathMaster

$36 n^{2} - 25$

Rewrite $36 n^{2}$ as ${(6 n)}^{2}$ .

${(6 n)}^{2} - 25$

Rewrite $25$ as $5^{2}$ .

${(6 n)}^{2} - 5^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 6 n$ and $b = 5$ .

$(6 n + 5) (6 n - 5)$

Factor 36n^2-25

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