Factor b^2-16 - MathMaster

$b^{2} - 16$

Rewrite $16$ as $4^{2}$ .

$b^{2} - 4^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = b$ and $b = 4$ .

$(b + 4) (b - 4)$

Factor b^2-16

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