Factor (x-3)^2-4 - MathMaster

${(x - 3)}^{2} - 4$

Rewrite $4$ as $2^{2}$ .

${(x - 3)}^{2} - 2^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x - 3$ and $b = 2$ .

$(x - 3 + 2) (x - 3 - 2)$

Simplify.

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Add $- 3$ and $2$ .

$(x - 1) (x - 3 - 2)$

Subtract $2$ from $- 3$ .

$(x - 1) (x - 5)$

Factor (x-3)^2-4

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