Find a,b,c 0=5x-4x^2-2

$0 = 5 x - 4 x^{2} - 2$

Move all terms to the left side of the equation and simplify.

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Move all the expressions to the left side of the equation.

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Move $5 x$ to the left side of the equation by subtracting it from both sides.

$0 - 5 x = - 4 x^{2} - 4 x^{2} - 2$

Move $4 x^{2}$ to the left side of the equation by adding it to both sides.

$0 - 5 x + 4 x^{2} = - 2$

Move $2$ to the left side of the equation by adding it to both sides.

$0 - 5 x + 4 x^{2} + 2 = 0$

Subtract $5 x$ from $0$ .

$- 5 x + 4 x^{2} + 2 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 4$ , $b = - 5$ , $c = 2$

Find a,b,c 0=5x-4x^2-2

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