Find f(g(x)) f(x)=2x-8 , g(x)=(x+2)/8

$f (x) = 2 x - 8$ , $g (x) = \frac{x + 2}{8}$

Set up the composite result function.

$f (g (x))$

Evaluate $f (g (x))$ by substituting in the value of $g$ into $f$ .

$f (\frac{x + 2}{8}) = 2 (\frac{x + 2}{8}) - 8$

Cancel the common factor of $2$ .

Tap for more steps…

Factor $2$ out of $8$ .

$f (\frac{x + 2}{8}) = 2 (\frac{x + 2}{2 (4)}) - 8$

Cancel the common factor.

$f (\frac{x + 2}{8}) = 2 (\frac{x + 2}{2 \cdot 4}) - 8$

Rewrite the expression.

$f (\frac{x + 2}{8}) = \frac{x + 2}{4} - 8$

To write $- 8$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$f (\frac{x + 2}{8}) = \frac{x + 2}{4} - 8 \cdot \frac{4}{4}$

Simplify terms.

Tap for more steps…

Combine $- 8$ and $\frac{4}{4}$ .

$f (\frac{x + 2}{8}) = \frac{x + 2}{4} + \frac{- 8 \cdot 4}{4}$

Combine the numerators over the common denominator.

$f (\frac{x + 2}{8}) = \frac{x + 2 - 8 \cdot 4}{4}$

Simplify the numerator.

Tap for more steps…

Multiply $- 8$ by $4$ .

$f (\frac{x + 2}{8}) = \frac{x + 2 - 32}{4}$

Subtract $32$ from $2$ .

$f (\frac{x + 2}{8}) = \frac{x - 30}{4}$

Find f(g(x)) f(x)=2x-8 , g(x)=(x+2)/8

Download our
App from the store