Find the Anti-Derivative f(x) = square root of 2

$f (x) = \sqrt{2}$

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Set up the integral to solve.

$F (x) = \int \sqrt{2} d x$

Since $\sqrt{2}$ is constant with respect to $x$ , move $\sqrt{2}$ out of the integral.

$\sqrt{2} x + C$

The answer is the antiderivative of the function $f (x) = \sqrt{2}$ .

$F (x) =$ $\sqrt{2} x + C$

Find the Anti-Derivative f(x) = square root of 2

Download our
App from the store