Find the Area trapezoid (9)(5)(15)

 $\begin{array}{r} b_{1} = & 9 \\ b_{2} = & 5 \\ h = & 15 \end{array}$

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Substitute the values of the height $h = 15$ and bases ( $b_{1} = 9$ and $b_{2} = 5$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 15 \cdot (9 + 5)$

Combine $\frac{1}{2}$ and $15$ .

$\frac{15}{2} \cdot (9 + 5)$

Add $9$ and $5$ .

$\frac{15}{2} \cdot 14$

Cancel the common factor of $2$ .

Tap for more steps…

Factor $2$ out of $14$ .

$\frac{15}{2} \cdot (2 (7))$

Cancel the common factor.

$\frac{15}{2} \cdot (2 \cdot 7)$

Rewrite the expression.

$15 \cdot 7$

Multiply $15$ by $7$ .

$105$

Find the Area trapezoid (9)(5)(15)

Download our
App from the store