Find the Area triangle (2x+2)(x)

 $\begin{array}{r} b = & x \\ h = & 2 x + 2 \end{array}$

The area of a triangle is equal to $\frac{1}{2}$ the base times the height.

$\frac{1}{2} \cdot (b a s e) \cdot (h e i g h t)$

Substitute the values of the base $b = x$ and height $h = 2$ into the formula for the area of a triangle.

$\frac{1}{2} x \cdot 2$

Combine $\frac{1}{2}$ and $x$ .

$\frac{x}{2} \cdot 2$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{x}{2} \cdot 2$

Rewrite the expression.

$x$

$x {(x + 2)}^{2}$

Find the Area triangle (2x+2)(x)

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