Find the Area triangle (9)(1)

 $\begin{array}{r} b = & 1 \\ h = & 9 \end{array}$

The area of a triangle is equal to $\frac{1}{2}$ the base times the height.

$\frac{1}{2} \cdot (b a s e) \cdot (h e i g h t)$

Substitute the values of the base $b = 1$ and height $h = 9$ into the formula for the area of a triangle.

$\frac{1}{2} \cdot 1 \cdot 9$

Multiply $\frac{1}{2}$ by $1$ .

$\frac{1}{2} \cdot 9$

Combine $\frac{1}{2}$ and $9$ .

$\frac{9}{2}$

The result can be shown in multiple forms.

Exact Form:

$\frac{9}{2}$

Decimal Form:

$4.5$

Mixed Number Form:

$4 \frac{1}{2}$

Find the Area triangle (9)(1)

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