Find the Derivative – d/dx (e^x)/( natural log of x)

$\frac{e^{x}}{\ln (x)}$

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = e^{x}$ and $g (x) = \ln (x)$ .

$\frac{\ln (x) \frac{d}{d x} [e^{x}] - e^{x} \frac{d}{d x} [\ln (x)]}{\ln^{2} (x)}$

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$\frac{\ln (x) e^{x} - e^{x} \frac{d}{d x} [\ln (x)]}{\ln^{2} (x)}$

The derivative of $\ln (x)$ with respect to $x$ is $\frac{1}{x}$ .

$\frac{\ln (x) e^{x} - e^{x} \frac{1}{x}}{\ln^{2} (x)}$

Combine fractions.

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Combine $\frac{1}{x}$ and $e^{x}$ .

$\frac{\ln (x) e^{x} - \frac{e^{x}}{x}}{\ln^{2} (x)}$

Reorder factors in $\ln (x) e^{x} - \frac{e^{x}}{x}$ .

$\frac{e^{x} \ln (x) - \frac{e^{x}}{x}}{\ln^{2} (x)}$

Find the Derivative – d/dx (e^x)/( natural log of x)

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