Find the Derivative f(x)=sin(pi)

$f (x) = \sin (π)$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$\frac{d}{d x} [\sin (0)]$

The exact value of $\sin (0)$ is $0$ .

$\frac{d}{d x} [0]$

Since $0$ is constant with respect to $x$ , the derivative of $0$ with respect to $x$ is $0$ .

$0$

Find the Derivative f(x)=sin(pi)

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