Find the Discriminant 2x+5x^2=1

$2 x + 5 x^{2} = 1$

Move $1$ to the left side of the equation by subtracting it from both sides.

$2 x + 5 x^{2} - 1 = 0$

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Substitute in the values of $a$ , $b$ , and $c$ .

$2^{2} - 4 (5 \cdot - 1)$

Evaluate the result to find the discriminant.

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Simplify each term.

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Raise $2$ to the power of $2$ .

$4 - 4 (5 \cdot - 1)$

Multiply $5$ by $- 1$ .

$4 - 4 \cdot - 5$

Multiply $- 4$ by $- 5$ .

$4 + 20$

Add $4$ and $20$ .

$24$

Find the Discriminant 2x+5x^2=1

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