Set the argument in greater than to find where the expression is defined.

Find all the values where the expression switches from negative to positive by setting each factor equal to and solving.

Subtract from both sides of the equation.

Add to both sides of the equation.

Solve for each factor to find the values where the absolute value expression goes from negative to positive.

Consolidate the solutions.

Find the domain of .

Set the denominator in equal to to find where the expression is undefined.

Add to both sides of the equation.

The domain is all values of that make the expression defined.

Interval Notation:

Interval Notation:

Use each root to create test intervals.

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

Test a value on the interval to see if it makes the inequality true.

Choose a value on the interval and see if this value makes the original inequality true.

Replace with in the original inequality.

The left side is greater than the right side , which means that the given statement is always true.

True

True

Test a value on the interval to see if it makes the inequality true.

Choose a value on the interval and see if this value makes the original inequality true.

Replace with in the original inequality.

The left side is not greater than the right side , which means that the given statement is false.

False

False

Test a value on the interval to see if it makes the inequality true.

Choose a value on the interval and see if this value makes the original inequality true.

Replace with in the original inequality.

The left side is greater than the right side , which means that the given statement is always true.

True

True

Compare the intervals to determine which ones satisfy the original inequality.

True

False

True

True

False

True

The solution consists of all of the true intervals.

or

or

Set the denominator in equal to to find where the expression is undefined.

Add to both sides of the equation.

The domain is all values of that make the expression defined.

Interval Notation:

Set-Builder Notation:

Find the Domain f(x) = log of (x+5)/(x-1)