Set the argument in greater than to find where the expression is defined.

Subtract from both sides of the inequality.

Divide each term by and simplify.

Divide each term in by .

Cancel the common factor of .

Cancel the common factor.

Divide by .

Move the negative in front of the fraction.

The solution consists of all of the true intervals.

The domain is all values of that make the expression defined.

Interval Notation:

Set-Builder Notation:

Find the Domain y = log of 8+3x