Find the Exact Value sin(pi/4-pi/6)

$\sin (\frac{π}{4} - \frac{π}{6})$

To write $\frac{π}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\sin (\frac{π}{4} \cdot \frac{3}{3} - \frac{π}{6})$

To write $\frac{π}{6}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\sin (\frac{π}{4} \cdot \frac{3}{3} - \frac{π}{6} \cdot \frac{2}{2})$

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

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Combine.

$\sin (\frac{π \cdot 3}{4 \cdot 3} - \frac{π}{6} \cdot \frac{2}{2})$

Multiply $4$ by $3$ .

$\sin (\frac{π \cdot 3}{12} - \frac{π}{6} \cdot \frac{2}{2})$

Combine.

$\sin (\frac{π \cdot 3}{12} - \frac{π \cdot 2}{6 \cdot 2})$

Multiply $6$ by $2$ .

$\sin (\frac{π \cdot 3}{12} - \frac{π \cdot 2}{12})$

Combine the numerators over the common denominator.

$\sin (\frac{π \cdot 3 - π \cdot 2}{12})$

Simplify the numerator.

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Move $3$ to the left of $π$ .

$\sin (\frac{3 \cdot π - π \cdot 2}{12})$

Multiply $2$ by $- 1$ .

$\sin (\frac{3 π - 2 π}{12})$

Subtract $2 π$ from $3 π$ .

$\sin (\frac{π}{12})$

The exact value of $\sin (\frac{π}{12})$ is $\frac{\sqrt{6} - \sqrt{2}}{4}$ .

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Split $\frac{π}{12}$ into two angles where the values of the six trigonometric functions are known.

$\sin (\frac{π}{4} - \frac{π}{6})$

Apply the difference of angles identity.

$\sin (\frac{π}{4}) \cos (\frac{π}{6}) - \cos (\frac{π}{4}) \sin (\frac{π}{6})$

The exact value of $\sin (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{2}}{2} \cos (\frac{π}{6}) - \cos (\frac{π}{4}) \sin (\frac{π}{6})$

The exact value of $\cos (\frac{π}{6})$ is $\frac{\sqrt{3}}{2}$ .

$\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \cos (\frac{π}{4}) \sin (\frac{π}{6})$

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \sin (\frac{π}{6})$

The exact value of $\sin (\frac{π}{6})$ is $\frac{1}{2}$ .

$\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$

Simplify $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Simplify each term.

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Multiply $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}$ .

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Multiply $\frac{\sqrt{2}}{2}$ and $\frac{\sqrt{3}}{2}$ .

$\frac{\sqrt{2} \sqrt{3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$

Combine using the product rule for radicals.

$\frac{\sqrt{2 \cdot 3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$

Multiply $2$ by $3$ .

$\frac{\sqrt{6}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$

Multiply $2$ by $2$ .

$\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$

Multiply $- \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Multiply $\frac{1}{2}$ and $\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2 \cdot 2}$

Multiply $2$ by $2$ .

$\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4}$

Combine the numerators over the common denominator.

$\frac{\sqrt{6} - \sqrt{2}}{4}$

The result can be shown in multiple forms.

Exact Form:

$\frac{\sqrt{6} - \sqrt{2}}{4}$

Decimal Form:

$0.25881904 \dots$

Find the Exact Value sin(pi/4-pi/6)

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