Find the Integral 2 square root of x

$2 \sqrt{x}$

Since $2$ is constant with respect to $x$ , move $2$ out of the integral.

$2 \int \sqrt{x} d x$

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$2 \int x^{\frac{1}{2}} d x$

By the Power Rule, the integral of $x^{\frac{1}{2}}$ with respect to $x$ is $\frac{2}{3} x^{\frac{3}{2}}$ .

$2 (\frac{2}{3} x^{\frac{3}{2}} + C)$

Simplify the answer.

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Simplify.

$2 (\frac{2}{3} x^{\frac{3}{2}}) + C$

Simplify.

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Combine $\frac{2}{3}$ and $x^{\frac{3}{2}}$ .

$2 \frac{2 x^{\frac{3}{2}}}{3} + C$

Combine $2$ and $\frac{2 x^{\frac{3}{2}}}{3}$ .

$\frac{2 (2 x^{\frac{3}{2}})}{3} + C$

Multiply $2$ by $2$ .

$\frac{4 x^{\frac{3}{2}}}{3} + C$

Reorder terms.

$\frac{4}{3} x^{\frac{3}{2}} + C$

Find the Integral 2 square root of x

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