Find the Integral 3/(x^2)

$\frac{3}{x^{2}}$

Since $3$ is constant with respect to $x$ , move $3$ out of the integral.

$3 \int \frac{1}{x^{2}} d x$

Apply basic rules of exponents.

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Move $x^{2}$ out of the denominator by raising it to the $- 1$ power.

$3 \int {(x^{2})}^{- 1} d x$

Multiply the exponents in ${(x^{2})}^{- 1}$ .

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Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$3 \int x^{2 \cdot - 1} d x$

Multiply $2$ by $- 1$ .

$3 \int x^{- 2} d x$

By the Power Rule, the integral of $x^{- 2}$ with respect to $x$ is $- x^{- 1}$ .

$3 (- x^{- 1} + C)$

Simplify the answer.

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Rewrite $3 (- x^{- 1} + C)$ as $3 (- \frac{1}{x}) + C$ .

$3 (- \frac{1}{x}) + C$

Simplify.

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Multiply $- 1$ by $3$ .

$- 3 \frac{1}{x} + C$

Combine $- 3$ and $\frac{1}{x}$ .

$\frac{- 3}{x} + C$

Move the negative in front of the fraction.

$- \frac{3}{x} + C$

Find the Integral 3/(x^2)

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