# Find the Lower or First Quartile 28 , 30 , 27 , 48 , 42 , 46 , 35 , 53 , 30 , 43 , 32 , 37 , 33 , 51 , 59 , 29 , 42

28 , 30 , 27 , 48 , 42 , 46 , 35 , 53 , 30 , 43 , 32 , 37 , 33 , 51 , 59 , 29 , 42
There are 17 observations, so the median is the middle number of the arranged set of data. Splitting the observations either side of the median gives two groups of observations. The median of the lower half of data is the lower or first quartile. The median of the upper half of data is the upper or third quartile.
The median of the lower half of data is the lower or first quartile
The median of the upper half of data is the upper or third quartile
Arrange the terms in ascending order.
27,28,29,30,30,32,33,35,37,42,42,43,46,48,51,53,59
The median is the middle term in the arranged data set.
37
The lower half of data is the set below the median.
27,28,29,30,30,32,33,35
The median for the lower half of data 27,28,29,30,30,32,33,35 is the lower or first quartile. In this case, the first quartile is 30.
The median is the middle term in the arranged data set. In the case of an even number of terms, the median is the average of the two middle terms.
30+302
Remove parentheses.
30+302
Cancel the common factor of 30+30 and 2.
Factor 2 out of 30.
2⋅15+302
Factor 2 out of 30.
2⋅15+2⋅152
Factor 2 out of 2⋅15+2⋅15.
2⋅(15+15)2
Cancel the common factors.
Factor 2 out of 2.
2⋅(15+15)2(1)
Cancel the common factor.
2⋅(15+15)2⋅1
Rewrite the expression.
15+151
Divide 15+15 by 1.
15+15
15+15
15+15
30
Convert the median 30 to decimal.
30
30
Find the Lower or First Quartile 28 , 30 , 27 , 48 , 42 , 46 , 35 , 53 , 30 , 43 , 32 , 37 , 33 , 51 , 59 , 29 , 42

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