Find the Maximum/Minimum Value P=3x+2y

$P = 3 x + 2 y$

Rewrite the equation as $3 x + 2 y = P$ .

$3 x + 2 y = P$

Subtract $3 x$ from both sides of the equation.

$2 y = P - 3 x$

Divide each term by $2$ and simplify.

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Divide each term in $2 y = P - 3 x$ by $2$ .

$\frac{2 y}{2} = \frac{P}{2} + \frac{- 3 x}{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 y}{2} = \frac{P}{2} + \frac{- 3 x}{2}$

Divide $y$ by $1$ .

$y = \frac{P}{2} + \frac{- 3 x}{2}$

Move the negative in front of the fraction.

$y = \frac{P}{2} - \frac{3 x}{2}$

The minimum and maximum cannot be determined because this is not a quadratic function.

Not a Quadratic Function

Find the Maximum/Minimum Value P=3x+2y

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