Find the Surface Area cylinder (14)(6)

Math
h=14r=6
The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of π⋅r2, plus the area of the side. The area of the side is equal to the area of a rectangle with length 2πr (the circumference of the base) times the height.
2π⋅(radius)2+2π⋅(radius)⋅(height)
Substitute the values of the radius r=6 and height h=14 into the formula. Pi π is approximately equal to 3.14.
2(π)(6)2+2(π)(6)(14)
Simplify each term.
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Raise 6 to the power of 2.
2π⋅36+2(π)(6)(14)
Multiply 36 by 2.
72π+2(π)(6)(14)
Multiply 6 by 2.
72π+12π⋅14
Multiply 14 by 12.
72π+168π
72π+168π
Add 72π and 168π.
240π
The result can be shown in multiple forms.
Exact Form:
240π
Decimal Form:
753.98223686…
Find the Surface Area cylinder (14)(6)

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