Find the Tangent Line at the Point x^3+y^3-6xy=0 , (4/3,8/3)

$x^{3} + y^{3} - 6 x y = 0$ , $(\frac{4}{3}, \frac{8}{3})$

Find $\frac{d y}{d x}$ and evaluate at $x = \frac{4}{3}$ and $y = \frac{8}{3}$ to find the slope of the tangent line at $x = \frac{4}{3}$ and $y = \frac{8}{3}$ .

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Differentiate both sides of the equation.

$\frac{d}{d x} (x^{3} + y^{3} - 6 x y) = \frac{d}{d x} (0)$

Differentiate the left side of the equation.

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Differentiate.

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By the Sum Rule, the derivative of $x^{3} + y^{3} - 6 x y$ with respect to $x$ is $\frac{d}{d x} [x^{3}] + \frac{d}{d x} [y^{3}] + \frac{d}{d x} [- 6 x y]$ .

$\frac{d}{d x} [x^{3}] + \frac{d}{d x} [y^{3}] + \frac{d}{d x} [- 6 x y]$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$3 x^{2} + \frac{d}{d x} [y^{3}] + \frac{d}{d x} [- 6 x y]$

Evaluate $\frac{d}{d x} [y^{3}]$ .

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Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = y$ .

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To apply the Chain Rule, set $u$ as $y$ .

$3 x^{2} + \frac{d}{d u} [u^{3}] \frac{d}{d x} [y] + \frac{d}{d x} [- 6 x y]$

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 3$ .

$3 x^{2} + 3 u^{2} \frac{d}{d x} [y] + \frac{d}{d x} [- 6 x y]$

Replace all occurrences of $u$ with $y$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] + \frac{d}{d x} [- 6 x y]$

Rewrite $\frac{d}{d x} [y]$ as $\frac{d}{d x} [y]$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] + \frac{d}{d x} [- 6 x y]$

Evaluate $\frac{d}{d x} [- 6 x y]$ .

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Since $- 6$ is constant with respect to $x$ , the derivative of $- 6 x y$ with respect to $x$ is $- 6 \frac{d}{d x} [x y]$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] - 6 \frac{d}{d x} [x y]$

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = y$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] - 6 (x \frac{d}{d x} [y] + y \frac{d}{d x} [x])$

Rewrite $\frac{d}{d x} [y]$ as $\frac{d}{d x} [y]$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] - 6 (x \frac{d}{d x} [y] + y \frac{d}{d x} [x])$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] - 6 (x \frac{d}{d x} [y] + y \cdot 1)$

Multiply $y$ by $1$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] - 6 (x \frac{d}{d x} [y] + y)$

Simplify.

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Apply the distributive property.

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] - 6 (x \frac{d}{d x} [y]) - 6 y$

Remove unnecessary parentheses.

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y] - 6 x \frac{d}{d x} [y] - 6 y$

Since $0$ is constant with respect to $x$ , the derivative of $0$ with respect to $x$ is $0$ .

$0$

Reform the equation by setting the left side equal to the right side.

$3 x^{2} + 3 y^{2} y' - 6 x y' - 6 y = 0$

Solve for $y'$ .

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Move all terms not containing $y'$ to the right side of the equation.

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Subtract $3 x^{2}$ from both sides of the equation.

$3 y^{2} y' - 6 x y' - 6 y = - 3 x^{2}$

Add $6 y$ to both sides of the equation.

$3 y^{2} y' - 6 x y' = - 3 x^{2} + 6 y$

Factor $3 y'$ out of $3 y^{2} y' - 6 x y'$ .

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Factor $3 y'$ out of $3 y^{2} y'$ .

$3 y' (y^{2}) - 6 x y' = - 3 x^{2} + 6 y$

Factor $3 y'$ out of $- 6 x y'$ .

$3 y' (y^{2}) + 3 y' (- 2 x) = - 3 x^{2} + 6 y$

Factor $3 y'$ out of $3 y' y^{2} + 3 y' (- 2 x)$ .

$3 y' (y^{2} - 2 x) = - 3 x^{2} + 6 y$

Divide each term by $3 (y^{2} - 2 x)$ and simplify.

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Divide each term in $3 y' (y^{2} - 2 x) = - 3 x^{2} + 6 y$ by $3 (y^{2} - 2 x)$ .

$\frac{3 y' (y^{2} - 2 x)}{3 (y^{2} - 2 x)} = \frac{- 3 x^{2}}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$

Simplify $\frac{3 y' (y^{2} - 2 x)}{3 (y^{2} - 2 x)}$ .

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Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 y' (y^{2} - 2 x)}{3 (y^{2} - 2 x)} = \frac{- 3 x^{2}}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$

Rewrite the expression.

$\frac{y' (y^{2} - 2 x)}{y^{2} - 2 x} = \frac{- 3 x^{2}}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$

Cancel the common factor of $y^{2} - 2 x$ .

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Cancel the common factor.

$\frac{y' (y^{2} - 2 x)}{y^{2} - 2 x} = \frac{- 3 x^{2}}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$

Divide $y'$ by $1$ .

$y' = \frac{- 3 x^{2}}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$

Simplify $\frac{- 3 x^{2}}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$ .

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Simplify each term.

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Cancel the common factor of $- 3$ and $3$ .

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Factor $3$ out of $- 3 x^{2}$ .

$y' = \frac{3 (- x^{2})}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$

Cancel the common factors.

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Cancel the common factor.

$y' = \frac{3 (- x^{2})}{3 (y^{2} - 2 x)} + \frac{6 y}{3 (y^{2} - 2 x)}$

Rewrite the expression.

$y' = \frac{- x^{2}}{y^{2} - 2 x} + \frac{6 y}{3 (y^{2} - 2 x)}$

Move the negative in front of the fraction.

$y' = - \frac{x^{2}}{y^{2} - 2 x} + \frac{6 y}{3 (y^{2} - 2 x)}$

Cancel the common factor of $6$ and $3$ .

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Factor $3$ out of $6 y$ .

$y' = - \frac{x^{2}}{y^{2} - 2 x} + \frac{3 (2 y)}{3 (y^{2} - 2 x)}$

Cancel the common factors.

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Cancel the common factor.

$y' = - \frac{x^{2}}{y^{2} - 2 x} + \frac{3 (2 y)}{3 (y^{2} - 2 x)}$

Rewrite the expression.

$y' = - \frac{x^{2}}{y^{2} - 2 x} + \frac{2 y}{y^{2} - 2 x}$

Simplify terms.

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Combine the numerators over the common denominator.

$y' = \frac{- x^{2} + 2 y}{y^{2} - 2 x}$

Factor $- 1$ out of $- x^{2}$ .

$y' = \frac{- (x^{2}) + 2 y}{y^{2} - 2 x}$

Factor $- 1$ out of $2 y$ .

$y' = \frac{- (x^{2}) - (- 2 y)}{y^{2} - 2 x}$

Factor $- 1$ out of $- (x^{2}) - (- 2 y)$ .

$y' = \frac{- (x^{2} - 2 y)}{y^{2} - 2 x}$

Simplify the expression.

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Rewrite $- (x^{2} - 2 y)$ as $- 1 (x^{2} - 2 y)$ .

$y' = \frac{- 1 (x^{2} - 2 y)}{y^{2} - 2 x}$

Move the negative in front of the fraction.

$y' = - \frac{x^{2} - 2 y}{y^{2} - 2 x}$

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{x^{2} - 2 y}{y^{2} - 2 x}$

Evaluate at $x = \frac{4}{3}$ and $y = \frac{8}{3}$ .

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Replace the variable $x$ with $\frac{4}{3}$ in the expression.

$- \frac{{(\frac{4}{3})}^{2} - 2 y}{y^{2} - 2 (\frac{4}{3})}$

Replace the variable $y$ with $\frac{8}{3}$ in the expression.

$- \frac{{(\frac{4}{3})}^{2} - 2 (\frac{8}{3})}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Simplify the numerator.

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Apply the product rule to $\frac{4}{3}$ .

$- \frac{\frac{4^{2}}{3^{2}} - 2 (\frac{8}{3})}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Raise $4$ to the power of $2$ .

$- \frac{\frac{16}{3^{2}} - 2 (\frac{8}{3})}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Raise $3$ to the power of $2$ .

$- \frac{\frac{16}{9} - 2 (\frac{8}{3})}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Multiply $- 2 (\frac{8}{3})$ .

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Combine $- 2$ and $\frac{8}{3}$ .

$- \frac{\frac{16}{9} + \frac{- 2 \cdot 8}{3}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Multiply $- 2$ by $8$ .

$- \frac{\frac{16}{9} + \frac{- 16}{3}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Move the negative in front of the fraction.

$- \frac{\frac{16}{9} - \frac{16}{3}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

To write $- \frac{16}{3}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{\frac{16}{9} - \frac{16}{3} \cdot \frac{3}{3}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Write each expression with a common denominator of $9$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{16}{3}$ and $\frac{3}{3}$ .

$- \frac{\frac{16}{9} - \frac{16 \cdot 3}{3 \cdot 3}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Multiply $3$ by $3$ .

$- \frac{\frac{16}{9} - \frac{16 \cdot 3}{9}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Combine the numerators over the common denominator.

$- \frac{\frac{16 - 16 \cdot 3}{9}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Simplify the numerator.

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Multiply $- 16$ by $3$ .

$- \frac{\frac{16 - 48}{9}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Subtract $48$ from $16$ .

$- \frac{\frac{- 32}{9}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Move the negative in front of the fraction.

$- \frac{- \frac{32}{9}}{{(\frac{8}{3})}^{2} - 2 (\frac{4}{3})}$

Simplify the denominator.

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Apply the product rule to $\frac{8}{3}$ .

$- \frac{- \frac{32}{9}}{\frac{8^{2}}{3^{2}} - 2 (\frac{4}{3})}$

Raise $8$ to the power of $2$ .

$- \frac{- \frac{32}{9}}{\frac{64}{3^{2}} - 2 (\frac{4}{3})}$

Raise $3$ to the power of $2$ .

$- \frac{- \frac{32}{9}}{\frac{64}{9} - 2 (\frac{4}{3})}$

Multiply $- 2 (\frac{4}{3})$ .

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Combine $- 2$ and $\frac{4}{3}$ .

$- \frac{- \frac{32}{9}}{\frac{64}{9} + \frac{- 2 \cdot 4}{3}}$

Multiply $- 2$ by $4$ .

$- \frac{- \frac{32}{9}}{\frac{64}{9} + \frac{- 8}{3}}$

Move the negative in front of the fraction.

$- \frac{- \frac{32}{9}}{\frac{64}{9} - \frac{8}{3}}$

To write $- \frac{8}{3}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{- \frac{32}{9}}{\frac{64}{9} - \frac{8}{3} \cdot \frac{3}{3}}$

Write each expression with a common denominator of $9$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{8}{3}$ and $\frac{3}{3}$ .

$- \frac{- \frac{32}{9}}{\frac{64}{9} - \frac{8 \cdot 3}{3 \cdot 3}}$

Multiply $3$ by $3$ .

$- \frac{- \frac{32}{9}}{\frac{64}{9} - \frac{8 \cdot 3}{9}}$

Combine the numerators over the common denominator.

$- \frac{- \frac{32}{9}}{\frac{64 - 8 \cdot 3}{9}}$

Simplify the numerator.

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Multiply $- 8$ by $3$ .

$- \frac{- \frac{32}{9}}{\frac{64 - 24}{9}}$

Subtract $24$ from $64$ .

$- \frac{- \frac{32}{9}}{\frac{40}{9}}$

Multiply the numerator by the reciprocal of the denominator.

$- (- \frac{32}{9} \cdot \frac{9}{40})$

Cancel the common factor of $8$ .

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Move the leading negative in $- \frac{32}{9}$ into the numerator.

$- (\frac{- 32}{9} \cdot \frac{9}{40})$

Factor $8$ out of $- 32$ .

$- (\frac{8 (- 4)}{9} \cdot \frac{9}{40})$

Factor $8$ out of $40$ .

$- (\frac{8 \cdot - 4}{9} \cdot \frac{9}{8 \cdot 5})$

Cancel the common factor.

$- (\frac{8 \cdot - 4}{9} \cdot \frac{9}{8 \cdot 5})$

Rewrite the expression.

$- (\frac{- 4}{9} \cdot \frac{9}{5})$

Cancel the common factor of $9$ .

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Cancel the common factor.

$- (\frac{- 4}{9} \cdot \frac{9}{5})$

Rewrite the expression.

$- (- 4 (\frac{1}{5}))$

Combine $- 4$ and $\frac{1}{5}$ .

$- \frac{- 4}{5}$

Move the negative in front of the fraction.

$- - \frac{4}{5}$

Multiply $- - \frac{4}{5}$ .

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Multiply $- 1$ by $- 1$ .

$1 (\frac{4}{5})$

Multiply $\frac{4}{5}$ by $1$ .

$\frac{4}{5}$

Plug in the slope of the tangent line and the $x$ and $y$ values of the point into the point–slope formula $y - y_{1} = m (x - x_{1})$ .

$y - (\frac{8}{3}) = \frac{4}{5} \cdot (x - (\frac{4}{3}))$

Simplify.

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The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Rewrite in slope-intercept form.

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Multiply $- 1$ by $\frac{8}{3}$ .

$y - \frac{8}{3} = \frac{4}{5} \cdot (x - (\frac{4}{3}))$

Simplify $\frac{4}{5} \cdot (x - (\frac{4}{3}))$ .

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Apply the distributive property.

$y - \frac{8}{3} = \frac{4}{5} x + \frac{4}{5} (- \frac{4}{3})$

Combine $\frac{4}{5}$ and $x$ .

$y - \frac{8}{3} = \frac{4 x}{5} + \frac{4}{5} (- \frac{4}{3})$

Multiply $\frac{4}{5} (- \frac{4}{3})$ .

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Multiply $\frac{4}{5}$ and $\frac{4}{3}$ .

$y - \frac{8}{3} = \frac{4 x}{5} - \frac{4 \cdot 4}{5 \cdot 3}$

Multiply $4$ by $4$ .

$y - \frac{8}{3} = \frac{4 x}{5} - \frac{16}{5 \cdot 3}$

Multiply $5$ by $3$ .

$y - \frac{8}{3} = \frac{4 x}{5} - \frac{16}{15}$

Move all terms not containing $y$ to the right side of the equation.

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Add $\frac{8}{3}$ to both sides of the equation.

$y = \frac{4 x}{5} - \frac{16}{15} + \frac{8}{3}$

To write $\frac{8}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$y = \frac{4 x}{5} - \frac{16}{15} + \frac{8}{3} \cdot \frac{5}{5}$

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{8}{3}$ and $\frac{5}{5}$ .

$y = \frac{4 x}{5} - \frac{16}{15} + \frac{8 \cdot 5}{3 \cdot 5}$

Multiply $3$ by $5$ .

$y = \frac{4 x}{5} - \frac{16}{15} + \frac{8 \cdot 5}{15}$

Combine the numerators over the common denominator.

$y = \frac{4 x}{5} + \frac{- 16 + 8 \cdot 5}{15}$

Simplify the numerator.

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Multiply $8$ by $5$ .

$y = \frac{4 x}{5} + \frac{- 16 + 40}{15}$

Add $- 16$ and $40$ .

$y = \frac{4 x}{5} + \frac{24}{15}$

Cancel the common factor of $24$ and $15$ .

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Factor $3$ out of $24$ .

$y = \frac{4 x}{5} + \frac{3 (8)}{15}$

Cancel the common factors.

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Factor $3$ out of $15$ .

$y = \frac{4 x}{5} + \frac{3 \cdot 8}{3 \cdot 5}$

Cancel the common factor.

$y = \frac{4 x}{5} + \frac{3 \cdot 8}{3 \cdot 5}$

Rewrite the expression.

$y = \frac{4 x}{5} + \frac{8}{5}$

Rewrite in slope-intercept form.

$y = \frac{4}{5} x + \frac{8}{5}$

Find the Tangent Line at the Point x^3+y^3-6xy=0 , (4/3,8/3)

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