Find the Upper or Third Quartile 7/4 , 1 , 2/3 , 4/5

Math
74 , 1 , 23 , 45
There are 4 observations, so the median is the mean of the two middle numbers of the arranged set of data. Splitting the observations either side of the median gives two groups of observations. The median of the lower half of data is the lower or first quartile. The median of the upper half of data is the upper or third quartile.
The median of the lower half of data is the lower or first quartile
The median of the upper half of data is the upper or third quartile
Arrange the terms in ascending order.
23,45,1,74
Find the median of 23,45,1,74.
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The median is the middle term in the arranged data set. In the case of an even number of terms, the median is the average of the two middle terms.
45+12
Remove parentheses.
45+12
Simplify the numerator.
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Write 1 as a fraction with a common denominator.
45+552
Combine the numerators over the common denominator.
4+552
Add 4 and 5.
952
952
Multiply the numerator by the reciprocal of the denominator.
95⋅12
Multiply 95⋅12.
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Multiply 95 and 12.
95⋅2
Multiply 5 by 2.
910
910
Convert the median 910 to decimal.
0.9
0.9
The upper half of data is the set above the median.
1,74
The median for the upper half of data 1,74 is the upper or third quartile. In this case, the third quartile is 1.375.
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The median is the middle term in the arranged data set. In the case of an even number of terms, the median is the average of the two middle terms.
1+742
Remove parentheses.
1+742
Simplify the numerator.
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Write 1 as a fraction with a common denominator.
44+742
Combine the numerators over the common denominator.
4+742
Add 4 and 7.
1142
1142
Multiply the numerator by the reciprocal of the denominator.
114⋅12
Multiply 114⋅12.
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Multiply 114 and 12.
114⋅2
Multiply 4 by 2.
118
118
Convert the median 118 to decimal.
1.375
1.375
Find the Upper or Third Quartile 7/4 , 1 , 2/3 , 4/5

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