Find the Vertex f(x)=(x-5)^2

$f (x) = {(x - 5)}^{2}$

Rewrite the equation in term of $x$ and $y$ .

$f (x) = {(x - 5)}^{2}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = 5$

$k = 0$

Find the vertex $(h, k)$ .

$(5, 0)$

Find the Vertex f(x)=(x-5)^2

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