Find the Vertex y=1/3(x-9)^2+5

$y = \frac{1}{3} {(x - 9)}^{2} + 5$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{1}{3}$

$h = 9$

$k = 5$

Find the vertex $(h, k)$ .

$(9, 5)$

Find the Vertex y=1/3(x-9)^2+5

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