Find the Vertex y=(x-4)^2

$y = {(x - 4)}^{2}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = 4$

$k = 0$

Find the vertex $(h, k)$ .

$(4, 0)$

Find the Vertex y=(x-4)^2

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