Find the X and Y Intercepts 9x^2+y^2=9

$9 x^{2} + y^{2} = 9$

Find the x-intercepts.

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To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$9 x^{2} + {(0)}^{2} = 9$

Solve the equation.

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Simplify $9 x^{2} + {(0)}^{2}$ .

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Raising $0$ to any positive power yields $0$ .

$9 x^{2} + 0 = 9$

Add $9 x^{2}$ and $0$ .

$9 x^{2} = 9$

Divide each term by $9$ and simplify.

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Divide each term in $9 x^{2} = 9$ by $9$ .

$\frac{9 x^{2}}{9} = \frac{9}{9}$

Cancel the common factor of $9$ .

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Cancel the common factor.

$\frac{9 x^{2}}{9} = \frac{9}{9}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{9}{9}$

Divide $9$ by $9$ .

$x^{2} = 1$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{1}$

The complete solution is the result of both the positive and negative portions of the solution.

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Any root of $1$ is $1$ .

$x = \pm 1$

The complete solution is the result of both the positive and negative portions of the solution.

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First, use the positive value of the $\pm$ to find the first solution.

$x = 1$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 1, - 1$

x-intercept(s) in point form.

x-intercept(s): $(1, 0), (- 1, 0)$

Find the y-intercepts.

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To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$9 {(0)}^{2} + y^{2} = 9$

Solve the equation.

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Simplify $9 {(0)}^{2} + y^{2}$ .

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Simplify each term.

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Raising $0$ to any positive power yields $0$ .

$9 \cdot 0 + y^{2} = 9$

Multiply $9$ by $0$ .

$0 + y^{2} = 9$

Add $0$ and $y^{2}$ .

$y^{2} = 9$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{9}$

The complete solution is the result of both the positive and negative portions of the solution.

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Simplify the right side of the equation.

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Rewrite $9$ as $3^{2}$ .

$y = \pm \sqrt{3^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm 3$

The complete solution is the result of both the positive and negative portions of the solution.

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First, use the positive value of the $\pm$ to find the first solution.

$y = 3$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - 3$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 3, - 3$

y-intercept(s) in point form.

y-intercept(s): $(0, 3), (0, - 3)$

List the intersections.

x-intercept(s): $(1, 0), (- 1, 0)$

y-intercept(s): $(0, 3), (0, - 3)$

Find the X and Y Intercepts 9x^2+y^2=9

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