2x+y=12

Subtract 2x from both sides of the equation.

y=12-2x

Choose any value for x that is in the domain to plug into the equation.

Remove parentheses.

y=12-2⋅0

Simplify 12-2⋅0.

Multiply -2 by 0.

y=12+0

Add 12 and 0.

y=12

y=12

Use the x and y values to form the ordered pair.

(0,12)

(0,12)

Remove parentheses.

y=12-2⋅1

Simplify 12-2⋅1.

Multiply -2 by 1.

y=12-2

Subtract 2 from 12.

y=10

y=10

Use the x and y values to form the ordered pair.

(1,10)

(1,10)

Remove parentheses.

y=12-2⋅2

Simplify 12-2⋅2.

Multiply -2 by 2.

y=12-4

Subtract 4 from 12.

y=8

y=8

Use the x and y values to form the ordered pair.

(2,8)

(2,8)

These are three possible solutions to the equation.

(0,12),(1,10),(2,8)

Find Three Ordered Pair Solutions 2x+y=12