# Find Three Ordered Pair Solutions 2x+y=12 2x+y=12
Subtract 2x from both sides of the equation.
y=12-2x
Choose any value for x that is in the domain to plug into the equation.
Choose 0 to substitute in for x to find the ordered pair.
Remove parentheses.
y=12-2⋅0
Simplify 12-2⋅0.
Multiply -2 by 0.
y=12+0
Add 12 and 0.
y=12
y=12
Use the x and y values to form the ordered pair.
(0,12)
(0,12)
Choose 1 to substitute in for x to find the ordered pair.
Remove parentheses.
y=12-2⋅1
Simplify 12-2⋅1.
Multiply -2 by 1.
y=12-2
Subtract 2 from 12.
y=10
y=10
Use the x and y values to form the ordered pair.
(1,10)
(1,10)
Choose 2 to substitute in for x to find the ordered pair.
Remove parentheses.
y=12-2⋅2
Simplify 12-2⋅2.
Multiply -2 by 2.
y=12-4
Subtract 4 from 12.
y=8
y=8
Use the x and y values to form the ordered pair.
(2,8)
(2,8)
These are three possible solutions to the equation.
(0,12),(1,10),(2,8)
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