Find Three Ordered Pair Solutions 4x+7y=-19

$4 x + 7 y = - 19$

Solve the equation for $y$ .

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Subtract $4 x$ from both sides of the equation.

$7 y = - 19 - 4 x$

Divide each term by $7$ and simplify.

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Divide each term in $7 y = - 19 - 4 x$ by $7$ .

$\frac{7 y}{7} = \frac{- 19}{7} + \frac{- 4 x}{7}$

Cancel the common factor of $7$ .

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Cancel the common factor.

$\frac{7 y}{7} = \frac{- 19}{7} + \frac{- 4 x}{7}$

Divide $y$ by $1$ .

$y = \frac{- 19}{7} + \frac{- 4 x}{7}$

Simplify each term.

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Move the negative in front of the fraction.

$y = - \frac{19}{7} + \frac{- 4 x}{7}$

Move the negative in front of the fraction.

$y = - \frac{19}{7} - \frac{4 x}{7}$

Choose any value for $x$ that is in the domain to plug into the equation.

Choose $0$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = - \frac{19}{7} - \frac{4 (0)}{7}$

Simplify $- \frac{19}{7} - \frac{4 (0)}{7}$ .

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Simplify each term.

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Cancel the common factor of $0$ and $7$ .

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Factor $7$ out of $4 (0)$ .

$y = - \frac{19}{7} - \frac{7 (4 \cdot (0))}{7}$

Cancel the common factors.

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Factor $7$ out of $7$ .

$y = - \frac{19}{7} - \frac{7 (4 \cdot (0))}{7 (1)}$

Cancel the common factor.

$y = - \frac{19}{7} - \frac{7 (4 \cdot (0))}{7 \cdot 1}$

Rewrite the expression.

$y = - \frac{19}{7} - \frac{4 \cdot (0)}{1}$

Divide $4 \cdot (0)$ by $1$ .

$y = - \frac{19}{7} - (4 \cdot (0))$

Multiply $4$ by $0$ .

$y = - \frac{19}{7} - 0$

Multiply $- 1$ by $0$ .

$y = - \frac{19}{7} + 0$

Add $- \frac{19}{7}$ and $0$ .

$y = - \frac{19}{7}$

Use the $x$ and $y$ values to form the ordered pair.

$(0, - \frac{19}{7})$

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = - \frac{19}{7} - \frac{4 (1)}{7}$

Simplify $- \frac{19}{7} - \frac{4 (1)}{7}$ .

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Multiply $4$ by $1$ .

$y = - \frac{19}{7} - \frac{4}{7}$

Combine the numerators over the common denominator.

$y = \frac{- 19 - 4}{7}$

Subtract $4$ from $- 19$ .

$y = \frac{- 23}{7}$

Move the negative in front of the fraction.

$y = - \frac{23}{7}$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - \frac{23}{7})$

Choose $2$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = - \frac{19}{7} - \frac{4 (2)}{7}$

Simplify $- \frac{19}{7} - \frac{4 (2)}{7}$ .

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Multiply $4$ by $2$ .

$y = - \frac{19}{7} - \frac{8}{7}$

Combine the numerators over the common denominator.

$y = \frac{- 19 - 8}{7}$

Subtract $8$ from $- 19$ .

$y = \frac{- 27}{7}$

Move the negative in front of the fraction.

$y = - \frac{27}{7}$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - \frac{27}{7})$

These are three possible solutions to the equation.

$(0, - \frac{19}{7}), (1, - \frac{23}{7}), (2, - \frac{27}{7})$

Find Three Ordered Pair Solutions 4x+7y=-19

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