Find Three Ordered Pair Solutions f(x)=x^2+3x+9

$f (x) = x^{2} + 3 x + 9$

Rewrite the function as an equation.

$y = x^{2} + 3 x + 9$

Choose any value for $x$ that is in the domain to plug into the equation.

Choose $0$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = {(0)}^{2} + 3 (0) + 9$

Simplify ${(0)}^{2} + 3 (0) + 9$ .

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Simplify each term.

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Raising $0$ to any positive power yields $0$ .

$y = 0 + 3 (0) + 9$

Multiply $3$ by $0$ .

$y = 0 + 0 + 9$

Simplify by adding zeros.

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Add $0$ and $0$ .

$y = 0 + 9$

Add $0$ and $9$ .

$y = 9$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 9)$

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = {(1)}^{2} + 3 (1) + 9$

Simplify ${(1)}^{2} + 3 (1) + 9$ .

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Simplify each term.

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One to any power is one.

$y = 1 + 3 (1) + 9$

Multiply $3$ by $1$ .

$y = 1 + 3 + 9$

Simplify by adding numbers.

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Add $1$ and $3$ .

$y = 4 + 9$

Add $4$ and $9$ .

$y = 13$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 13)$

Choose $2$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = {(2)}^{2} + 3 (2) + 9$

Simplify ${(2)}^{2} + 3 (2) + 9$ .

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Simplify each term.

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Raise $2$ to the power of $2$ .

$y = 4 + 3 (2) + 9$

Multiply $3$ by $2$ .

$y = 4 + 6 + 9$

Simplify by adding numbers.

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Add $4$ and $6$ .

$y = 10 + 9$

Add $10$ and $9$ .

$y = 19$

Use the $x$ and $y$ values to form the ordered pair.

$(2, 19)$

These are three possible solutions to the equation.

$(0, 9), (1, 13), (2, 19)$

Find Three Ordered Pair Solutions f(x)=x^2+3x+9

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